Both Arrays have to be sorted, in order to implement this case.
Comparing two arrays of element, smallest will occupy in new array.
Time Complexity is O(N^2)
public class Main
{
public static void main(String[] args) {
int[] arr1 = new int[]{1,5,9}; //Array-1
int[] arr2 = new int[]{2,3,10}; // Array-2
int m = arr1.length;
int n = arr2.length;
int[] arr3 = new int[m+n]; //Array-3
int i=0,j=0,k=0;
while(i<m && j<n)
{
if(arr1[i]<arr2[j]) //Comparing two arrays in-order to insert in array-3.
{
arr3[k] = arr1[i];
i++;
k++;
}
else{
arr3[k] = arr2[j];
k++;
j++;
}
}//By the end of the loop any one of two array is sorted if the elements left in any array we have to add while loop
while(i<m)
{
arr3[k] = arr1[i];
k++;
i++;
}
while(j<n)
{
arr3[k] = arr2[j];
j++;
k++;
}
//All Elements are added to the array-3.
for(int l=0;l<arr3.length;l++)
{
System.out.println(arr3[l]); //Printing the values of array-3.
}
}
}
// C program to implement merge sort
#include <stdio.h>
#include <stdlib.h>
void mergesort(int[],int,int);
void merge(int[],int,int,int);
int main() {
int a[10],n;
printf("Enter number of elements inside array :\\n");
scanf("%d",&n);
for(int i=0;i<n;i++)
{
printf("Enter element %d : \\n",i);
scanf("%d",&a[i]);
}
mergesort(a,0,n-1);
printf("\\n Sorted Array is : \\n");
for(int i=0;i<n;i++)
{
printf("%d\\n",a[i]);
}
return 0;
}
void mergesort(int a[],int low,int high)
{
int mid;
if(low<high){
mid=(low+high)/2;
mergesort(a,low,mid);
mergesort(a,mid+1,high);
merge(a,low,mid,high);
}
}
void merge(int a[],int low,int mid,int high)
{
int i,j,k,b[20];
i=low;
k=low;
j=mid+1;//3,5,6|4,2,6
while(i<=mid && j<=high)
{
if(a[i]<a[j])
{
b[k]=a[i];
i++;
k++;
}
else{
b[k]=a[j];
j++;
k++;
}
}
while(i<=mid)
{
b[k]=a[i];
i++;
k++;
}
while(j<=high)
{
b[k]=a[j];
j++;
k++;
}
for(int i=low;i<=high;i++)
{
a[i]=b[i];
}
}
/* Java program for Merge Sort */
class MergeSort
{
// Merges two subarrays of arr[].
// First subarray is arr[l..m]
// Second subarray is arr[m+1..r]
void merge(int arr[], int l, int m, int r)
{
// Find sizes of two subarrays to be merged
int n1 = m - l + 1;
int n2 = r - m;
/* Create temp arrays */
int L[] = new int [n1];
int R[] = new int [n2];
/*Copy data to temp arrays*/
for (int i=0; i<n1; ++i)
L[i] = arr[l + i];
for (int j=0; j<n2; ++j)
R[j] = arr[m + 1+ j];
/* Merge the temp arrays */
// Initial indexes of first and second subarrays
int i = 0, j = 0;
// Initial index of merged subarray array
int k = l;
while (i < n1 && j < n2)
{
if (L[i] <= R[j])
{
arr[k] = L[i];
i++;
}
else
{
arr[k] = R[j];
j++;
}
k++;
}
/* Copy remaining elements of L[] if any */
while (i < n1)
{
arr[k] = L[i];
i++;
k++;
}
/* Copy remaining elements of R[] if any */
while (j < n2)
{
arr[k] = R[j];
j++;
k++;
}
}
// Main function that sorts arr[l..r] using
// merge()
void sort(int arr[], int l, int r)
{
if (l < r)
{
// Find the middle point
int m = (l+r)/2;
// Sort first and second halves
sort(arr, l, m);
sort(arr , m+1, r);
// Merge the sorted halves
merge(arr, l, m, r);
}
}
/* A utility function to print array of size n */
static void printArray(int arr[])
{
int n = arr.length;
for (int i=0; i<n; ++i)
System.out.print(arr[i] + " ");
System.out.println();
}
// Driver method
public static void main(String args[])
{
int arr[] = {12, 11, 13, 5, 6, 7};
System.out.println("Given Array");
printArray(arr);
MergeSort ob = new MergeSort();
ob.sort(arr, 0, arr.length-1);
System.out.println("\\nSorted array");
printArray(arr);
}
}